cisco 4010

) { theTo[++cnt]=y; NEXT[CNT]=HEAD[X]; head[x]=CNT; * } $ intN,m,du[n];Panax Notoginseng voidinit () { -N=getint (); m=getint (); theCnt=0; Memset (Head,0,sizeofhead); +Memset (Du,0,sizeofdu); A intx, y; theF (I,1, M) { +X=getint (); y=getint (); - swap (x, y); $Add (x, y); du[y]++; $ } - } - intAns[n],tot; the voidsolve () { -priority_queueint>Q;WuyiF (I,1, N)if(!Du[i]) Q.push (i); thetot=0; - while(!Q.empty ()) { Wu intx=Q.top (); Q.pop (); -ans[++tot]=x; About fo

4010: [HNOI2015] food productionTime Limit:5 Sec Memory limit:512 MBsubmit:426 solved:242[Submit] [Status] [Discuss]DescriptionThe famous gourmet Small A is invited to the ATM Grand Hotel for its tasting dishes.The ATM Hotel prepares N-course dishes for small A, and the hotel offers a high-to-low quality food according to the1 to n sequential numbering, with the highest estimated quality of the dishes numbered 1. Because of the problem of taste colloc

4010: [HNOI2015] Food production time Limit: 5 Sec Memory Limit: MB Submit: 1199 Solved: 583 [Submit] [Status] [Discuss] DescriptionThe famous gourmet Small A is invited to the ATM Grand Hotel for its tasting dishes.The ATM hotel has a N-course menu for small A, and the hotel has a sequential number from 1 to n for the estimated quality of the dishes, with the highest estimated quality of the dishes numbered 1. Due to the pr

Topology sort + heap. Turn from POPOQQQ god Ben. Reverse build to run the topology sort and then output in reverse order. Why not come, because do not know to choose the current dish to make which vegetables first. In reverse order to run the topology, you can also ensure that the limit is met the number of small in front. Off-topic: I have finished the third example of the output is not correct, a look at the problem directly abandoned therapy. It turns out that a few letters are changed .... T

HDOJ question 4010 Query on The Trees (Link Cut Tree connection, edge deletion, path point addition, maximum path point weight), hdoj4010Query on The TreesTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others)Total Submission (s): 3602 Accepted Submission (s): 1587Problem DescriptionWe have met so far problems on the tree, so today we will have a query problem on a set of trees.There are N nodes, each node will have a unique

4010: [HNOI2015] Food productionTime limit:20 Sec Memory limit:256 MBTopic ConnectionHttp://uoj.ac/problem/67DescriptionThe famous gourmet Small A is invited to the ATM Grand Hotel for its tasting dishes.The ATM hotel has a N-course menu for small A, and the hotel has a sequential number from 1 to n for the estimated quality of the dishes, with the highest estimated quality of the dishes numbered 1. Due to the problem of the taste collocation of the d

BZOJ 4010 HNOI2015 dish production Topology Sorting + heap, bzojhnoi2015 Given an undirected graph, find a topological order so that:1 is at the topMake sure that 2 is at the top of the list under the above conditions.Make sure that the top 3 position is the top 3 under the above conditions.......Note that it is not the smallest Lexicographic Order! Example 3 Create a reverse graph, find the largest topological order of the Lexicographic Order of the

Question: A tree is provided with four operations: 1. If X and Y are not in the same tree, they are connected to XY. 2. If X and Y are in the same tree and X! = Y, then convert X to the root of the tree and separate y from Y's father. 3. If X and Y are in the same tree, then all vertex weights from X to Y + W 4. If X and Y are in the same tree, the maximum values from X to Y are output. Dynamic Tree entry question: # Include View code HDU 4010. quer

. Given two integer x, y, you shoshould make a new edge between these two node X and Y. So after this operation, two trees will be connected to a new one. 2. given two integer x, y, you shoshould find the tree in the tree set who contain node X, And You shoshould make the node X be the root of this tree, and then you shoshould cut the edge between node y and its parent. so after this operation, a tree will be separate into two parts. 3. given three integer W, X, Y, for the X, Y and all nodes bet

;>1]) Swap (heap[t],heap[t>>1]), t1;Else Break; } }}voidTopology_sort () {using namespacePriority_queue;intI for(i=1; iif(!degree[i]) Insert (i); while(Priority_queue::top) {intx=heap[1]; Pop ();Stack[++::top]=x; for(I=head[x];i;i=table[i].next)if(!--degree[table[i].to]) Insert (table[i].to); }}intMain () {intT,i,x,y; for(Cin>>T; T t--) {Initialize ();scanf("%d%d", n,m); for(i=1; iscanf("%d%d", x,y); ADD (Y,X); degree[x]++; } top=0; Topology_sort ();if(top

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Half a year five acquisitions Cisco intensive integration for self-redemptionWu MicroCisco, a "takeover guru", recently announced a new deal.The acquisition was Cloudlock, a cloud security company, with a total transaction price of $293 million. This is the fifth takeover deal that Cisco has launched this year.As the world's largest network equipment manufacturer, Cisco